Integrand size = 19, antiderivative size = 121 \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=\frac {3}{8} b \left (4 a^2+b^2\right ) x-\frac {a \left (a^2+4 b^2\right ) \cos (e+f x)}{2 f}-\frac {b \left (2 a^2+3 b^2\right ) \cos (e+f x) \sin (e+f x)}{8 f}-\frac {a \cos (e+f x) (a+b \sin (e+f x))^2}{4 f}-\frac {\cos (e+f x) (a+b \sin (e+f x))^3}{4 f} \]
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Time = 0.09 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {2832, 2813} \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=-\frac {a \left (a^2+4 b^2\right ) \cos (e+f x)}{2 f}-\frac {b \left (2 a^2+3 b^2\right ) \sin (e+f x) \cos (e+f x)}{8 f}+\frac {3}{8} b x \left (4 a^2+b^2\right )-\frac {\cos (e+f x) (a+b \sin (e+f x))^3}{4 f}-\frac {a \cos (e+f x) (a+b \sin (e+f x))^2}{4 f} \]
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Rule 2813
Rule 2832
Rubi steps \begin{align*} \text {integral}& = -\frac {\cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac {1}{4} \int (3 b+3 a \sin (e+f x)) (a+b \sin (e+f x))^2 \, dx \\ & = -\frac {a \cos (e+f x) (a+b \sin (e+f x))^2}{4 f}-\frac {\cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac {1}{12} \int (a+b \sin (e+f x)) \left (15 a b+3 \left (2 a^2+3 b^2\right ) \sin (e+f x)\right ) \, dx \\ & = \frac {3}{8} b \left (4 a^2+b^2\right ) x-\frac {a \left (a^2+4 b^2\right ) \cos (e+f x)}{2 f}-\frac {b \left (2 a^2+3 b^2\right ) \cos (e+f x) \sin (e+f x)}{8 f}-\frac {a \cos (e+f x) (a+b \sin (e+f x))^2}{4 f}-\frac {\cos (e+f x) (a+b \sin (e+f x))^3}{4 f} \\ \end{align*}
Time = 0.45 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.83 \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=\frac {-8 a \left (4 a^2+9 b^2\right ) \cos (e+f x)+b \left (48 a^2 e+12 b^2 e+48 a^2 f x+12 b^2 f x+8 a b \cos (3 (e+f x))-8 \left (3 a^2+b^2\right ) \sin (2 (e+f x))+b^2 \sin (4 (e+f x))\right )}{32 f} \]
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Time = 1.66 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.86
method | result | size |
derivativedivides | \(\frac {-\cos \left (f x +e \right ) a^{3}+3 a^{2} b \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-a \,b^{2} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )+b^{3} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )}{f}\) | \(104\) |
default | \(\frac {-\cos \left (f x +e \right ) a^{3}+3 a^{2} b \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-a \,b^{2} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )+b^{3} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )}{f}\) | \(104\) |
parts | \(\frac {b^{3} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )}{f}-\frac {a^{3} \cos \left (f x +e \right )}{f}-\frac {a \,b^{2} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{f}+\frac {3 a^{2} b \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )}{f}\) | \(112\) |
parallelrisch | \(\frac {48 a^{2} b f x +12 b^{3} f x -32 \cos \left (f x +e \right ) a^{3}-72 \cos \left (f x +e \right ) a \,b^{2}+\sin \left (4 f x +4 e \right ) b^{3}+8 \cos \left (3 f x +3 e \right ) a \,b^{2}-24 \sin \left (2 f x +2 e \right ) a^{2} b -8 \sin \left (2 f x +2 e \right ) b^{3}-32 a^{3}-64 a \,b^{2}}{32 f}\) | \(113\) |
risch | \(\frac {3 a^{2} b x}{2}+\frac {3 b^{3} x}{8}-\frac {a^{3} \cos \left (f x +e \right )}{f}-\frac {9 a \,b^{2} \cos \left (f x +e \right )}{4 f}+\frac {b^{3} \sin \left (4 f x +4 e \right )}{32 f}+\frac {\cos \left (3 f x +3 e \right ) a \,b^{2}}{4 f}-\frac {3 b \sin \left (2 f x +2 e \right ) a^{2}}{4 f}-\frac {b^{3} \sin \left (2 f x +2 e \right )}{4 f}\) | \(114\) |
norman | \(\frac {\frac {\left (2 a^{3}+4 a \,b^{2}\right ) \left (\tan ^{8}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {3 b \left (4 a^{2}+b^{2}\right ) x}{8}+\frac {2 a^{3} \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {6 \left (a^{3}+2 a \,b^{2}\right ) \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {2 \left (3 a^{3}+8 a \,b^{2}\right ) \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}-\frac {3 b \left (4 a^{2}+b^{2}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{4 f}+\frac {3 b \left (4 a^{2}+b^{2}\right ) \left (\tan ^{7}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4 f}+\frac {3 b \left (4 a^{2}+b^{2}\right ) x \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}+\frac {9 b \left (4 a^{2}+b^{2}\right ) x \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4}+\frac {3 b \left (4 a^{2}+b^{2}\right ) x \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}+\frac {3 b \left (4 a^{2}+b^{2}\right ) x \left (\tan ^{8}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{8}-\frac {b \left (12 a^{2}+11 b^{2}\right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4 f}+\frac {b \left (12 a^{2}+11 b^{2}\right ) \left (\tan ^{5}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4 f}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{4}}\) | \(333\) |
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Time = 0.28 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.77 \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=\frac {8 \, a b^{2} \cos \left (f x + e\right )^{3} + 3 \, {\left (4 \, a^{2} b + b^{3}\right )} f x - 8 \, {\left (a^{3} + 3 \, a b^{2}\right )} \cos \left (f x + e\right ) + {\left (2 \, b^{3} \cos \left (f x + e\right )^{3} - {\left (12 \, a^{2} b + 5 \, b^{3}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{8 \, f} \]
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Leaf count of result is larger than twice the leaf count of optimal. 233 vs. \(2 (109) = 218\).
Time = 0.18 (sec) , antiderivative size = 233, normalized size of antiderivative = 1.93 \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=\begin {cases} - \frac {a^{3} \cos {\left (e + f x \right )}}{f} + \frac {3 a^{2} b x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {3 a^{2} b x \cos ^{2}{\left (e + f x \right )}}{2} - \frac {3 a^{2} b \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} - \frac {3 a b^{2} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {2 a b^{2} \cos ^{3}{\left (e + f x \right )}}{f} + \frac {3 b^{3} x \sin ^{4}{\left (e + f x \right )}}{8} + \frac {3 b^{3} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} + \frac {3 b^{3} x \cos ^{4}{\left (e + f x \right )}}{8} - \frac {5 b^{3} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{8 f} - \frac {3 b^{3} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} & \text {for}\: f \neq 0 \\x \left (a + b \sin {\left (e \right )}\right )^{3} \sin {\left (e \right )} & \text {otherwise} \end {cases} \]
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Time = 0.23 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.80 \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=\frac {24 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} b + 32 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a b^{2} + {\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} b^{3} - 32 \, a^{3} \cos \left (f x + e\right )}{32 \, f} \]
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Time = 0.29 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.79 \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=\frac {a b^{2} \cos \left (3 \, f x + 3 \, e\right )}{4 \, f} + \frac {b^{3} \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} + \frac {3}{8} \, {\left (4 \, a^{2} b + b^{3}\right )} x - \frac {{\left (4 \, a^{3} + 9 \, a b^{2}\right )} \cos \left (f x + e\right )}{4 \, f} - \frac {{\left (3 \, a^{2} b + b^{3}\right )} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \]
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Time = 7.72 (sec) , antiderivative size = 313, normalized size of antiderivative = 2.59 \[ \int \sin (e+f x) (a+b \sin (e+f x))^3 \, dx=\frac {3\,b\,\mathrm {atan}\left (\frac {3\,b\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (4\,a^2+b^2\right )}{4\,\left (3\,a^2\,b+\frac {3\,b^3}{4}\right )}\right )\,\left (4\,a^2+b^2\right )}{4\,f}-\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (3\,a^2\,b+\frac {3\,b^3}{4}\right )+2\,a^3\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6+4\,a\,b^2+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left (6\,a^3+12\,a\,b^2\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (6\,a^3+16\,a\,b^2\right )-{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7\,\left (3\,a^2\,b+\frac {3\,b^3}{4}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (3\,a^2\,b+\frac {11\,b^3}{4}\right )-{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,\left (3\,a^2\,b+\frac {11\,b^3}{4}\right )+2\,a^3}{f\,\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8+4\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6+6\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4+4\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+1\right )}-\frac {3\,b\,\left (4\,a^2+b^2\right )\,\left (\mathrm {atan}\left (\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )-\frac {f\,x}{2}\right )}{4\,f} \]
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